Optimal. Leaf size=143 \[ -\frac {a^2 A}{5 x^5}-\frac {a^2 B}{4 x^4}+x \left (C \left (2 a c+b^2\right )+2 A b c\right )-\frac {A \left (2 a c+b^2\right )+2 a b C}{x}-\frac {a (a C+2 A b)}{3 x^3}+B \log (x) \left (2 a c+b^2\right )-\frac {a b B}{x^2}+\frac {1}{3} c x^3 (A c+2 b C)+b B c x^2+\frac {1}{4} B c^2 x^4+\frac {1}{5} c^2 C x^5 \]
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Rubi [A] time = 0.15, antiderivative size = 143, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.036, Rules used = {1628} \[ -\frac {a^2 A}{5 x^5}-\frac {a^2 B}{4 x^4}+x \left (C \left (2 a c+b^2\right )+2 A b c\right )-\frac {A \left (2 a c+b^2\right )+2 a b C}{x}-\frac {a (a C+2 A b)}{3 x^3}+B \log (x) \left (2 a c+b^2\right )-\frac {a b B}{x^2}+\frac {1}{3} c x^3 (A c+2 b C)+b B c x^2+\frac {1}{4} B c^2 x^4+\frac {1}{5} c^2 C x^5 \]
Antiderivative was successfully verified.
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Rule 1628
Rubi steps
\begin {align*} \int \frac {\left (A+B x+C x^2\right ) \left (a+b x^2+c x^4\right )^2}{x^6} \, dx &=\int \left (2 A b c \left (1+\frac {b \left (1+\frac {2 a c}{b^2}\right ) C}{2 A c}\right )+\frac {a^2 A}{x^6}+\frac {a^2 B}{x^5}+\frac {a (2 A b+a C)}{x^4}+\frac {2 a b B}{x^3}+\frac {A \left (b^2+2 a c\right )+2 a b C}{x^2}+\frac {B \left (b^2+2 a c\right )}{x}+2 b B c x+c (A c+2 b C) x^2+B c^2 x^3+c^2 C x^4\right ) \, dx\\ &=-\frac {a^2 A}{5 x^5}-\frac {a^2 B}{4 x^4}-\frac {a (2 A b+a C)}{3 x^3}-\frac {a b B}{x^2}-\frac {A \left (b^2+2 a c\right )+2 a b C}{x}+\left (2 A b c+\left (b^2+2 a c\right ) C\right ) x+b B c x^2+\frac {1}{3} c (A c+2 b C) x^3+\frac {1}{4} B c^2 x^4+\frac {1}{5} c^2 C x^5+B \left (b^2+2 a c\right ) \log (x)\\ \end {align*}
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Mathematica [A] time = 0.08, size = 142, normalized size = 0.99 \[ -\frac {a^2 A}{5 x^5}-\frac {a^2 B}{4 x^4}-\frac {2 a A c+2 a b C+A b^2}{x}-\frac {a (a C+2 A b)}{3 x^3}+B \log (x) \left (2 a c+b^2\right )+C x \left (2 a c+b^2\right )-\frac {a b B}{x^2}+\frac {1}{3} c x^3 (A c+2 b C)+2 A b c x+b B c x^2+\frac {1}{4} B c^2 x^4+\frac {1}{5} c^2 C x^5 \]
Antiderivative was successfully verified.
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fricas [A] time = 0.76, size = 145, normalized size = 1.01 \[ \frac {12 \, C c^{2} x^{10} + 15 \, B c^{2} x^{9} + 60 \, B b c x^{7} + 20 \, {\left (2 \, C b c + A c^{2}\right )} x^{8} + 60 \, {\left (C b^{2} + 2 \, {\left (C a + A b\right )} c\right )} x^{6} + 60 \, {\left (B b^{2} + 2 \, B a c\right )} x^{5} \log \relax (x) - 60 \, B a b x^{3} - 60 \, {\left (2 \, C a b + A b^{2} + 2 \, A a c\right )} x^{4} - 15 \, B a^{2} x - 12 \, A a^{2} - 20 \, {\left (C a^{2} + 2 \, A a b\right )} x^{2}}{60 \, x^{5}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.29, size = 140, normalized size = 0.98 \[ \frac {1}{5} \, C c^{2} x^{5} + \frac {1}{4} \, B c^{2} x^{4} + \frac {2}{3} \, C b c x^{3} + \frac {1}{3} \, A c^{2} x^{3} + B b c x^{2} + C b^{2} x + 2 \, C a c x + 2 \, A b c x + {\left (B b^{2} + 2 \, B a c\right )} \log \left ({\left | x \right |}\right ) - \frac {60 \, B a b x^{3} + 60 \, {\left (2 \, C a b + A b^{2} + 2 \, A a c\right )} x^{4} + 15 \, B a^{2} x + 12 \, A a^{2} + 20 \, {\left (C a^{2} + 2 \, A a b\right )} x^{2}}{60 \, x^{5}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.01, size = 144, normalized size = 1.01 \[ \frac {C \,c^{2} x^{5}}{5}+\frac {B \,c^{2} x^{4}}{4}+\frac {A \,c^{2} x^{3}}{3}+\frac {2 C b c \,x^{3}}{3}+B b c \,x^{2}+2 A b c x +2 B a c \ln \relax (x )+B \,b^{2} \ln \relax (x )+2 C a c x +C \,b^{2} x -\frac {2 A a c}{x}-\frac {A \,b^{2}}{x}-\frac {2 C a b}{x}-\frac {B a b}{x^{2}}-\frac {2 A a b}{3 x^{3}}-\frac {C \,a^{2}}{3 x^{3}}-\frac {B \,a^{2}}{4 x^{4}}-\frac {A \,a^{2}}{5 x^{5}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.61, size = 138, normalized size = 0.97 \[ \frac {1}{5} \, C c^{2} x^{5} + \frac {1}{4} \, B c^{2} x^{4} + B b c x^{2} + \frac {1}{3} \, {\left (2 \, C b c + A c^{2}\right )} x^{3} + {\left (C b^{2} + 2 \, {\left (C a + A b\right )} c\right )} x + {\left (B b^{2} + 2 \, B a c\right )} \log \relax (x) - \frac {60 \, B a b x^{3} + 60 \, {\left (2 \, C a b + A b^{2} + 2 \, A a c\right )} x^{4} + 15 \, B a^{2} x + 12 \, A a^{2} + 20 \, {\left (C a^{2} + 2 \, A a b\right )} x^{2}}{60 \, x^{5}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.05, size = 136, normalized size = 0.95 \[ x^3\,\left (\frac {A\,c^2}{3}+\frac {2\,C\,b\,c}{3}\right )-\frac {x^2\,\left (\frac {C\,a^2}{3}+\frac {2\,A\,b\,a}{3}\right )+\frac {A\,a^2}{5}+x^4\,\left (A\,b^2+2\,C\,a\,b+2\,A\,a\,c\right )+\frac {B\,a^2\,x}{4}+B\,a\,b\,x^3}{x^5}+x\,\left (C\,b^2+2\,A\,c\,b+2\,C\,a\,c\right )+\ln \relax (x)\,\left (B\,b^2+2\,B\,a\,c\right )+\frac {B\,c^2\,x^4}{4}+\frac {C\,c^2\,x^5}{5}+B\,b\,c\,x^2 \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 7.81, size = 155, normalized size = 1.08 \[ B b c x^{2} + \frac {B c^{2} x^{4}}{4} + B \left (2 a c + b^{2}\right ) \log {\relax (x )} + \frac {C c^{2} x^{5}}{5} + x^{3} \left (\frac {A c^{2}}{3} + \frac {2 C b c}{3}\right ) + x \left (2 A b c + 2 C a c + C b^{2}\right ) + \frac {- 12 A a^{2} - 15 B a^{2} x - 60 B a b x^{3} + x^{4} \left (- 120 A a c - 60 A b^{2} - 120 C a b\right ) + x^{2} \left (- 40 A a b - 20 C a^{2}\right )}{60 x^{5}} \]
Verification of antiderivative is not currently implemented for this CAS.
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